Yup, no foolin'
We will be staying at the Hyatt Place Titusville / Kennedy Space Center. Check under the "Travel & Hotel" section for a link to a discount code.
The bride and groom kindly request an unplugged ceremony. Please turn off all devices and enjoy being fully present in the moment. That said, we will reserve an announced few minutes during the ceremony for you to take your own pictures and then ask for you to put your phones away for the remainder of the ceremony. After the ceremony - please feel free to use your cellphones as much as your heart desires! We just don't want our professional ceremony photos to look like every concert since 2015.
In this problem, we know that one train starts two hours before the other one and travels at a known rate. Let's calculate how far it goes in those two hours: d = rt = 2 hrs * 60 mi/hr = 120 mi The time is now 7:00 and the trains are 455 - 120 = 335 mi apart. Now both trains are moving, one traveling at 60 mi/hr and the other at 70 mi/hr. Their closing speed is just 60 + 70 = 130 mi/hr, and the total distance to go is 335 mi. Solve the rate equation for t to get t = d/r. Plug in 335 for d and 130 for r. Time to collision is t = 325 / 130 = 2.5769 hrs. That's 2 hours with a remainder of 0.5769 0.5769 * 60 minutes = 34.615 minutes 0.615 * 60 seconds = 37 seconds The time of collision will thus be the sum of 2 hrs + 2.5769 hrs added to the 5:00 starting time. Tc = 5:00 + 4.5769 = 5:00 + 4:00 + 0:34 + 0:00:37 = 9:34:37